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-16x^2+100x=154
We move all terms to the left:
-16x^2+100x-(154)=0
a = -16; b = 100; c = -154;
Δ = b2-4ac
Δ = 1002-4·(-16)·(-154)
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{144}=12$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(100)-12}{2*-16}=\frac{-112}{-32} =3+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(100)+12}{2*-16}=\frac{-88}{-32} =2+3/4 $
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